13[3-(2-2x)]+x=3(9x+5)-2

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Solution for 13[3-(2-2x)]+x=3(9x+5)-2 equation:


Simplifying
13[3 + -1(2 + -2x)] + x = 3(9x + 5) + -2
13[3 + (2 * -1 + -2x * -1)] + x = 3(9x + 5) + -2
13[3 + (-2 + 2x)] + x = 3(9x + 5) + -2

Combine like terms: 3 + -2 = 1
13[1 + 2x] + x = 3(9x + 5) + -2
[1 * 13 + 2x * 13] + x = 3(9x + 5) + -2
[13 + 26x] + x = 3(9x + 5) + -2

Combine like terms: 26x + x = 27x
13 + 27x = 3(9x + 5) + -2

Reorder the terms:
13 + 27x = 3(5 + 9x) + -2
13 + 27x = (5 * 3 + 9x * 3) + -2
13 + 27x = (15 + 27x) + -2

Reorder the terms:
13 + 27x = 15 + -2 + 27x

Combine like terms: 15 + -2 = 13
13 + 27x = 13 + 27x

Add '-13' to each side of the equation.
13 + -13 + 27x = 13 + -13 + 27x

Combine like terms: 13 + -13 = 0
0 + 27x = 13 + -13 + 27x
27x = 13 + -13 + 27x

Combine like terms: 13 + -13 = 0
27x = 0 + 27x
27x = 27x

Add '-27x' to each side of the equation.
27x + -27x = 27x + -27x

Combine like terms: 27x + -27x = 0
0 = 27x + -27x

Combine like terms: 27x + -27x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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